Lee is a town in Madison County, Florida, United States. The Town of Lee is part of the Florida Panhandle in North Florida. The population was 375 at the 2020 census.
2010 and 2020 census
{| class="wikitable"
|+Lee racial composition<br> (Hispanics excluded from racial categories)<br> (NH = Non-Hispanic)<br>
!Race
!Pop 2010
!Pop 2020
!% 2010
!% 2020
|-
|White (NH)
|266
|287
|75.57%
|76.53%
|-
|Black or African American (NH)
|27
|29
|7.67%
|7.73%
|-
|Native American or Alaska Native (NH)
|2
|3
|0.57%
|0.80%
|-
|Asian (NH)
|3
|5
|0.85%
|1.33%
|-
|Pacific Islander or Native Hawaiian (NH)
|0
|0
|0.00%
|0.00%
|-
|Some other race (NH)
|0
|2
|0.00%
|0.53%
|-
|Two or more races/Multiracial (NH)
|8
|23
|2.27%
|6.13%
|-
|Hispanic or Latino (any race)
|46
|26
|13.07%
|6.93%
|-
|Total
|352
|375
|
|
|-
|}
As of the 2020 United States census, there were 375 people, 212 households, and 122 families residing in the town.
As of the 2010 United States census, there were 352 people, 176 households, and 156 families residing in the town.
2000 census
At the 2000 census there were 352 people, 130 households, and 92 families in the town. The population density was . There were 154 housing units at an average density of . The racial makeup of the town was 95.45% White, 2.84% African American, 0.28% Native American, 0.28% Asian, and 1.14% from two or more races. Hispanic or Latino of any race were 2.56%.