Hardin is a city in Liberty County, Texas, United States. Its population was 768 at the 2020 census.<br> 1850–1900 1910<br> 1920 1930 1940<br>
1950 1960 1970<br> 1980 1990 2000<br> 2010
2020 census
As of the 2020 census, Hardin had a population of 768, 295 households, and 183 families residing in the city.
The median age was 37.1 years. 24.7% of residents were under the age of 18 and 17.6% of residents were 65 years of age or older. For every 100 females there were 92.5 males, and for every 100 females age 18 and over there were 98.6 males age 18 and over.
There were 295 households in Hardin, of which 36.3% had children under the age of 18 living in them. Of all households, 50.8% were married-couple households, 19.3% were households with a male householder and no spouse or partner present, and 25.4% were households with a female householder and no spouse or partner present. About 18.0% of all households were made up of individuals and 11.2% had someone living alone who was 65 years of age or older.
! Race !! Number !! Percent
|-
| White || 656 || 85.4%
|-
| Black or African American || 14 || 1.8%
|-
| American Indian and Alaska Native || 5 || 0.7%
|-
| Asian || 2 || 0.3%
|-
| Native Hawaiian and Other Pacific Islander || 0 || 0.0%
|-
| Some other race || 52 || 6.8%
|-
| Two or more races || 39 || 5.1%
|-
| Hispanic or Latino (of any race) || 88 || 11.5%
|}
2000 census
As of the 2000 census